(3/m+1)=(1/m^2-1)

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Solution for (3/m+1)=(1/m^2-1) equation: 


D( m )

m^2 = 0

m = 0

m^2 = 0

m^2 = 0

1*m^2 = 0 // : 1

m^2 = 0

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

3/m+1 = 1/(m^2)-1 // - 1/(m^2)-1

3/m-(1/(m^2))+1+1 = 0

3/m-m^-2+1+1 = 0

3*m^-1-m^-2+2 = 0

t_1 = m^-1

3*t_1^1-1*t_1^2+2 = 0

3*t_1-t_1^2+2 = 0

DELTA = 3^2-(-1*2*4)

DELTA = 17

DELTA > 0

t_1 = (17^(1/2)-3)/(-1*2) or t_1 = (-17^(1/2)-3)/(-1*2)

t_1 = (17^(1/2)-3)/(-2) or t_1 = (17^(1/2)+3)/2

t_1 = (17^(1/2)-3)/(-2)

m^-1-((17^(1/2)-3)/(-2)) = 0

1*m^-1 = (17^(1/2)-3)/(-2) // : 1

m^-1 = (17^(1/2)-3)/(-2)

-1 < 0

1/(m^1) = (17^(1/2)-3)/(-2) // * m^1

1 = ((17^(1/2)-3)/(-2))*m^1 // : (17^(1/2)-3)/(-2)

-2*(17^(1/2)-3)^-1 = m^1

m = -2*(17^(1/2)-3)^-1

t_1 = (17^(1/2)+3)/2

m^-1-((17^(1/2)+3)/2) = 0

1*m^-1 = (17^(1/2)+3)/2 // : 1

m^-1 = (17^(1/2)+3)/2

-1 < 0

1/(m^1) = (17^(1/2)+3)/2 // * m^1

1 = ((17^(1/2)+3)/2)*m^1 // : (17^(1/2)+3)/2

2*(17^(1/2)+3)^-1 = m^1

m = 2*(17^(1/2)+3)^-1

m in { -2*(17^(1/2)-3)^-1, 2*(17^(1/2)+3)^-1 }

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